X^2-20x+72=2x

Solution for X^2-20x+72=2x equation:

X^2-20X+72=2X

We move all terms to the left:

X^2-20X+72-(2X)=0

We add all the numbers together, and all the variables

X^2-22X+72=0

a = 1; b = -22; c = +72;
Δ = b2-4ac
Δ = -222-4·1·72
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-14}{2*1}=\frac{8}{2}
=4
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+14}{2*1}=\frac{36}{2}
=18
$